6(3x+1)+2(3x-5)=20

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Solution for 6(3x+1)+2(3x-5)=20 equation: 



6(3x+1)+2(3x-5)=20

We move all terms to the left:

6(3x+1)+2(3x-5)-(20)=0

We multiply parentheses

18x+6x+6-10-20=0

We add all the numbers together, and all the variables

24x-24=0

We move all terms containing x to the left, all other terms to the right

24x=24

x=24/24

x=1

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