6(3t+1)-15=t-(t+8)

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Solution for 6(3t+1)-15=t-(t+8) equation: 



6(3t+1)-15=t-(t+8)

We move all terms to the left:

6(3t+1)-15-(t-(t+8))=0

We multiply parentheses

18t-(t-(t+8))+6-15=0



We calculate terms in parentheses: -(t-(t+8)), so:

t-(t+8)

We get rid of parentheses

t-t-8

We add all the numbers together, and all the variables

-8

Back to the equation:

-(-8)



We add all the numbers together, and all the variables

18t-1=0

We move all terms containing t to the left, all other terms to the right

18t=1

t=1/18

t=1/18

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