6(3p+1)=7p+17

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Solution for 6(3p+1)=7p+17 equation: 



6(3p+1)=7p+17

We move all terms to the left:

6(3p+1)-(7p+17)=0

We multiply parentheses

18p-(7p+17)+6=0

We get rid of parentheses

18p-7p-17+6=0

We add all the numbers together, and all the variables

11p-11=0

We move all terms containing p to the left, all other terms to the right

11p=11

p=11/11

p=1

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