6(3p+1)-4=9(3p-2)+11

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Solution for 6(3p+1)-4=9(3p-2)+11 equation:



6(3p+1)-4=9(3p-2)+11
We move all terms to the left:
6(3p+1)-4-(9(3p-2)+11)=0
We multiply parentheses
18p-(9(3p-2)+11)+6-4=0
We calculate terms in parentheses: -(9(3p-2)+11), so:
9(3p-2)+11
We multiply parentheses
27p-18+11
We add all the numbers together, and all the variables
27p-7
Back to the equation:
-(27p-7)
We add all the numbers together, and all the variables
18p-(27p-7)+2=0
We get rid of parentheses
18p-27p+7+2=0
We add all the numbers together, and all the variables
-9p+9=0
We move all terms containing p to the left, all other terms to the right
-9p=-9
p=-9/-9
p=1

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