6(3n-4)=(7n+5)+1

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Solution for 6(3n-4)=(7n+5)+1 equation: 



6(3n-4)=(7n+5)+1

We move all terms to the left:

6(3n-4)-((7n+5)+1)=0

We multiply parentheses

18n-((7n+5)+1)-24=0



We calculate terms in parentheses: -((7n+5)+1), so:

(7n+5)+1

We get rid of parentheses

7n+5+1

We add all the numbers together, and all the variables

7n+6

Back to the equation:

-(7n+6)



We get rid of parentheses

18n-7n-6-24=0

We add all the numbers together, and all the variables

11n-30=0

We move all terms containing n to the left, all other terms to the right

11n=30

n=30/11

n=2+8/11

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