6(3n-4)=(7n+3)+4

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Solution for 6(3n-4)=(7n+3)+4 equation: 



6(3n-4)=(7n+3)+4

We move all terms to the left:

6(3n-4)-((7n+3)+4)=0

We multiply parentheses

18n-((7n+3)+4)-24=0



We calculate terms in parentheses: -((7n+3)+4), so:

(7n+3)+4

We get rid of parentheses

7n+3+4

We add all the numbers together, and all the variables

7n+7

Back to the equation:

-(7n+7)



We get rid of parentheses

18n-7n-7-24=0

We add all the numbers together, and all the variables

11n-31=0

We move all terms containing n to the left, all other terms to the right

11n=31

n=31/11

n=2+9/11

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