6(3n+1)-3(-1-2n)=n+2n

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Solution for 6(3n+1)-3(-1-2n)=n+2n equation: 



6(3n+1)-3(-1-2n)=n+2n

We move all terms to the left:

6(3n+1)-3(-1-2n)-(n+2n)=0

We add all the numbers together, and all the variables

6(3n+1)-3(-2n-1)-(+3n)=0

We multiply parentheses

18n+6n-(+3n)+6+3=0

We get rid of parentheses

18n+6n-3n+6+3=0

We add all the numbers together, and all the variables

21n+9=0

We move all terms containing n to the left, all other terms to the right

21n=-9

n=-9/21

n=-3/7

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