6(3j-2)=-12+18j

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Solution for 6(3j-2)=-12+18j equation: 



6(3j-2)=-12+18j

We move all terms to the left:

6(3j-2)-(-12+18j)=0

We add all the numbers together, and all the variables

6(3j-2)-(18j-12)=0

We multiply parentheses

18j-(18j-12)-12=0

We get rid of parentheses

18j-18j+12-12=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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