6(3g+1)-30=3(2g-4)

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Solution for 6(3g+1)-30=3(2g-4) equation: 



6(3g+1)-30=3(2g-4)

We move all terms to the left:

6(3g+1)-30-(3(2g-4))=0

We multiply parentheses

18g-(3(2g-4))+6-30=0



We calculate terms in parentheses: -(3(2g-4)), so:

3(2g-4)

We multiply parentheses

6g-12

Back to the equation:

-(6g-12)



We add all the numbers together, and all the variables

18g-(6g-12)-24=0

We get rid of parentheses

18g-6g+12-24=0

We add all the numbers together, and all the variables

12g-12=0

We move all terms containing g to the left, all other terms to the right

12g=12

g=12/12

g=1

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