6(3f-5)=7(3f-2)

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Solution for 6(3f-5)=7(3f-2) equation: 



6(3f-5)=7(3f-2)

We move all terms to the left:

6(3f-5)-(7(3f-2))=0

We multiply parentheses

18f-(7(3f-2))-30=0



We calculate terms in parentheses: -(7(3f-2)), so:

7(3f-2)

We multiply parentheses

21f-14

Back to the equation:

-(21f-14)



We get rid of parentheses

18f-21f+14-30=0

We add all the numbers together, and all the variables

-3f-16=0

We move all terms containing f to the left, all other terms to the right

-3f=16

f=16/-3

f=-5+1/3

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