6(3b-4)+8(2b-5)=140

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Solution for 6(3b-4)+8(2b-5)=140 equation:


Simplifying
6(3b + -4) + 8(2b + -5) = 140

Reorder the terms:
6(-4 + 3b) + 8(2b + -5) = 140
(-4 * 6 + 3b * 6) + 8(2b + -5) = 140
(-24 + 18b) + 8(2b + -5) = 140

Reorder the terms:
-24 + 18b + 8(-5 + 2b) = 140
-24 + 18b + (-5 * 8 + 2b * 8) = 140
-24 + 18b + (-40 + 16b) = 140

Reorder the terms:
-24 + -40 + 18b + 16b = 140

Combine like terms: -24 + -40 = -64
-64 + 18b + 16b = 140

Combine like terms: 18b + 16b = 34b
-64 + 34b = 140

Solving
-64 + 34b = 140

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '64' to each side of the equation.
-64 + 64 + 34b = 140 + 64

Combine like terms: -64 + 64 = 0
0 + 34b = 140 + 64
34b = 140 + 64

Combine like terms: 140 + 64 = 204
34b = 204

Divide each side by '34'.
b = 6

Simplifying
b = 6

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