6(3b-4)+8(2b-40)=140

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Solution for 6(3b-4)+8(2b-40)=140 equation: 



6(3b-4)+8(2b-40)=140

We move all terms to the left:

6(3b-4)+8(2b-40)-(140)=0

We multiply parentheses

18b+16b-24-320-140=0

We add all the numbers together, and all the variables

34b-484=0

We move all terms containing b to the left, all other terms to the right

34b=484

b=484/34

b=14+4/17

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