6(3b+5)-6=-192

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Solution for 6(3b+5)-6=-192 equation: 



6(3b+5)-6=-192

We move all terms to the left:

6(3b+5)-6-(-192)=0

We add all the numbers together, and all the variables

6(3b+5)+186=0

We multiply parentheses

18b+30+186=0

We add all the numbers together, and all the variables

18b+216=0

We move all terms containing b to the left, all other terms to the right

18b=-216

b=-216/18

b=-12

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