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6(3a+2)=2(4a+11)

We move all terms to the left:

6(3a+2)-(2(4a+11))=0

We multiply parentheses

18a-(2(4a+11))+12=0

We calculate terms in parentheses: -(2(4a+11)), so:We get rid of parentheses

2(4a+11)

We multiply parentheses

8a+22

Back to the equation:

-(8a+22)

18a-8a-22+12=0

We add all the numbers together, and all the variables

10a-10=0

We move all terms containing a to the left, all other terms to the right

10a=10

a=10/10

a=1

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