6(36-y)+y=(36-y)+5y

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Solution for 6(36-y)+y=(36-y)+5y equation: 



6(36-y)+y=(36-y)+5y

We move all terms to the left:

6(36-y)+y-((36-y)+5y)=0

We add all the numbers together, and all the variables

6(-1y+36)+y-((-1y+36)+5y)=0

We add all the numbers together, and all the variables

y+6(-1y+36)-((-1y+36)+5y)=0

We multiply parentheses

y-6y-((-1y+36)+5y)+216=0



We calculate terms in parentheses: -((-1y+36)+5y), so:

(-1y+36)+5y

We add all the numbers together, and all the variables

5y+(-1y+36)

We get rid of parentheses

5y-1y+36

We add all the numbers together, and all the variables

4y+36

Back to the equation:

-(4y+36)



We add all the numbers together, and all the variables

-5y-(4y+36)+216=0

We get rid of parentheses

-5y-4y-36+216=0

We add all the numbers together, and all the variables

-9y+180=0

We move all terms containing y to the left, all other terms to the right

-9y=-180

y=-180/-9

y=+20

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