6(3+x)=2(3-x)+4x

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Solution for 6(3+x)=2(3-x)+4x equation: 



6(3+x)=2(3-x)+4x

We move all terms to the left:

6(3+x)-(2(3-x)+4x)=0

We add all the numbers together, and all the variables

6(x+3)-(2(-1x+3)+4x)=0

We multiply parentheses

6x-(2(-1x+3)+4x)+18=0



We calculate terms in parentheses: -(2(-1x+3)+4x), so:

2(-1x+3)+4x

We add all the numbers together, and all the variables

4x+2(-1x+3)

We multiply parentheses

4x-2x+6

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

6x-2x-6+18=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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