6(3+x)=(1+x)

Solution for 6(3+x)=(1+x) equation:

6(3+x)=(1+x)

We move all terms to the left:

6(3+x)-((1+x))=0

We add all the numbers together, and all the variables

6(x+3)-((x+1))=0

We multiply parentheses

6x-((x+1))+18=0


We calculate terms in parentheses: -((x+1)), so:

(x+1)

We get rid of parentheses

x+1

Back to the equation:

-(x+1)


We get rid of parentheses

6x-x-1+18=0

We add all the numbers together, and all the variables

5x+17=0

We move all terms containing x to the left, all other terms to the right

5x=-17

x=-17/5

x=-3+2/5