6(3+a4)=7(4+a5)

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Solution for 6(3+a4)=7(4+a5) equation: 



6(3+a4)=7(4+a5)

We move all terms to the left:

6(3+a4)-(7(4+a5))=0

We add all the numbers together, and all the variables

6(+a^4+3)-(7(+a^5+4))=0

We multiply parentheses

6a^4-(7(+a^5+4))+18=0



We calculate terms in parentheses: -(7(+a^5+4)), so:

7(+a^5+4)

We do not support eapression: a^5

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