6(2z-5)=30

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Solution for 6(2z-5)=30 equation: 



6(2z-5)=30

We move all terms to the left:

6(2z-5)-(30)=0

We multiply parentheses

12z-30-30=0

We add all the numbers together, and all the variables

12z-60=0

We move all terms containing z to the left, all other terms to the right

12z=60

z=60/12

z=5

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