6(2z-1)-5(z+2)=3(z+1)

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Solution for 6(2z-1)-5(z+2)=3(z+1) equation:


Simplifying
6(2z + -1) + -5(z + 2) = 3(z + 1)

Reorder the terms:
6(-1 + 2z) + -5(z + 2) = 3(z + 1)
(-1 * 6 + 2z * 6) + -5(z + 2) = 3(z + 1)
(-6 + 12z) + -5(z + 2) = 3(z + 1)

Reorder the terms:
-6 + 12z + -5(2 + z) = 3(z + 1)
-6 + 12z + (2 * -5 + z * -5) = 3(z + 1)
-6 + 12z + (-10 + -5z) = 3(z + 1)

Reorder the terms:
-6 + -10 + 12z + -5z = 3(z + 1)

Combine like terms: -6 + -10 = -16
-16 + 12z + -5z = 3(z + 1)

Combine like terms: 12z + -5z = 7z
-16 + 7z = 3(z + 1)

Reorder the terms:
-16 + 7z = 3(1 + z)
-16 + 7z = (1 * 3 + z * 3)
-16 + 7z = (3 + 3z)

Solving
-16 + 7z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-16 + 7z + -3z = 3 + 3z + -3z

Combine like terms: 7z + -3z = 4z
-16 + 4z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-16 + 4z = 3 + 0
-16 + 4z = 3

Add '16' to each side of the equation.
-16 + 16 + 4z = 3 + 16

Combine like terms: -16 + 16 = 0
0 + 4z = 3 + 16
4z = 3 + 16

Combine like terms: 3 + 16 = 19
4z = 19

Divide each side by '4'.
z = 4.75

Simplifying
z = 4.75

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