6(2z-1)-3(z+4)=4(z+1)

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Solution for 6(2z-1)-3(z+4)=4(z+1) equation:


Simplifying
6(2z + -1) + -3(z + 4) = 4(z + 1)

Reorder the terms:
6(-1 + 2z) + -3(z + 4) = 4(z + 1)
(-1 * 6 + 2z * 6) + -3(z + 4) = 4(z + 1)
(-6 + 12z) + -3(z + 4) = 4(z + 1)

Reorder the terms:
-6 + 12z + -3(4 + z) = 4(z + 1)
-6 + 12z + (4 * -3 + z * -3) = 4(z + 1)
-6 + 12z + (-12 + -3z) = 4(z + 1)

Reorder the terms:
-6 + -12 + 12z + -3z = 4(z + 1)

Combine like terms: -6 + -12 = -18
-18 + 12z + -3z = 4(z + 1)

Combine like terms: 12z + -3z = 9z
-18 + 9z = 4(z + 1)

Reorder the terms:
-18 + 9z = 4(1 + z)
-18 + 9z = (1 * 4 + z * 4)
-18 + 9z = (4 + 4z)

Solving
-18 + 9z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-18 + 9z + -4z = 4 + 4z + -4z

Combine like terms: 9z + -4z = 5z
-18 + 5z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-18 + 5z = 4 + 0
-18 + 5z = 4

Add '18' to each side of the equation.
-18 + 18 + 5z = 4 + 18

Combine like terms: -18 + 18 = 0
0 + 5z = 4 + 18
5z = 4 + 18

Combine like terms: 4 + 18 = 22
5z = 22

Divide each side by '5'.
z = 4.4

Simplifying
z = 4.4

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