6(2z-1)-3(z+2)=7(z+1)

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Solution for 6(2z-1)-3(z+2)=7(z+1) equation:


Simplifying
6(2z + -1) + -3(z + 2) = 7(z + 1)

Reorder the terms:
6(-1 + 2z) + -3(z + 2) = 7(z + 1)
(-1 * 6 + 2z * 6) + -3(z + 2) = 7(z + 1)
(-6 + 12z) + -3(z + 2) = 7(z + 1)

Reorder the terms:
-6 + 12z + -3(2 + z) = 7(z + 1)
-6 + 12z + (2 * -3 + z * -3) = 7(z + 1)
-6 + 12z + (-6 + -3z) = 7(z + 1)

Reorder the terms:
-6 + -6 + 12z + -3z = 7(z + 1)

Combine like terms: -6 + -6 = -12
-12 + 12z + -3z = 7(z + 1)

Combine like terms: 12z + -3z = 9z
-12 + 9z = 7(z + 1)

Reorder the terms:
-12 + 9z = 7(1 + z)
-12 + 9z = (1 * 7 + z * 7)
-12 + 9z = (7 + 7z)

Solving
-12 + 9z = 7 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-12 + 9z + -7z = 7 + 7z + -7z

Combine like terms: 9z + -7z = 2z
-12 + 2z = 7 + 7z + -7z

Combine like terms: 7z + -7z = 0
-12 + 2z = 7 + 0
-12 + 2z = 7

Add '12' to each side of the equation.
-12 + 12 + 2z = 7 + 12

Combine like terms: -12 + 12 = 0
0 + 2z = 7 + 12
2z = 7 + 12

Combine like terms: 7 + 12 = 19
2z = 19

Divide each side by '2'.
z = 9.5

Simplifying
z = 9.5

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