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6(2z+4)=4(-2z+6)
We move all terms to the left:
6(2z+4)-(4(-2z+6))=0
We multiply parentheses
12z-(4(-2z+6))+24=0
We calculate terms in parentheses: -(4(-2z+6)), so:We get rid of parentheses
4(-2z+6)
We multiply parentheses
-8z+24
Back to the equation:
-(-8z+24)
12z+8z-24+24=0
We add all the numbers together, and all the variables
20z=0
z=0/20
z=0
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