6(2y-3)-5=(y+1)

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Solution for 6(2y-3)-5=(y+1) equation: 



6(2y-3)-5=(y+1)

We move all terms to the left:

6(2y-3)-5-((y+1))=0

We multiply parentheses

12y-((y+1))-18-5=0



We calculate terms in parentheses: -((y+1)), so:

(y+1)

We get rid of parentheses

y+1

Back to the equation:

-(y+1)



We add all the numbers together, and all the variables

12y-(y+1)-23=0

We get rid of parentheses

12y-y-1-23=0

We add all the numbers together, and all the variables

11y-24=0

We move all terms containing y to the left, all other terms to the right

11y=24

y=24/11

y=2+2/11

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