6(2y+3)=4(y-5)

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Solution for 6(2y+3)=4(y-5) equation: 



6(2y+3)=4(y-5)

We move all terms to the left:

6(2y+3)-(4(y-5))=0

We multiply parentheses

12y-(4(y-5))+18=0



We calculate terms in parentheses: -(4(y-5)), so:

4(y-5)

We multiply parentheses

4y-20

Back to the equation:

-(4y-20)



We get rid of parentheses

12y-4y+20+18=0

We add all the numbers together, and all the variables

8y+38=0

We move all terms containing y to the left, all other terms to the right

8y=-38

y=-38/8

y=-4+3/4

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