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6(2y+3)=2(5y+8)
We move all terms to the left:
6(2y+3)-(2(5y+8))=0
We multiply parentheses
12y-(2(5y+8))+18=0
We calculate terms in parentheses: -(2(5y+8)), so:We get rid of parentheses
2(5y+8)
We multiply parentheses
10y+16
Back to the equation:
-(10y+16)
12y-10y-16+18=0
We add all the numbers together, and all the variables
2y+2=0
We move all terms containing y to the left, all other terms to the right
2y=-2
y=-2/2
y=-1
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