6(2y+1)=3(4y+2)

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Solution for 6(2y+1)=3(4y+2) equation: 



6(2y+1)=3(4y+2)

We move all terms to the left:

6(2y+1)-(3(4y+2))=0

We multiply parentheses

12y-(3(4y+2))+6=0



We calculate terms in parentheses: -(3(4y+2)), so:

3(4y+2)

We multiply parentheses

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

12y-12y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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