6(2y)=10(3y-8)

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Solution for 6(2y)=10(3y-8) equation: 



6(2y)=10(3y-8)

We move all terms to the left:

6(2y)-(10(3y-8))=0



We calculate terms in parentheses: -(10(3y-8)), so:

10(3y-8)

We multiply parentheses

30y-80

Back to the equation:

-(30y-80)



We get rid of parentheses

62y-30y+80=0

We add all the numbers together, and all the variables

32y+80=0

We move all terms containing y to the left, all other terms to the right

32y=-80

y=-80/32

y=-2+1/2

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