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6(2x/3)+6(16/3)=6(-4x/2)
We move all terms to the left:
6(2x/3)+6(16/3)-(6(-4x/2))=0
We add all the numbers together, and all the variables
6(+2x/3)-(6(-4x/2))+6(+16/3)=0
We add all the numbers together, and all the variables
6(+2x/3)-(6(-4x/2))+2=0
We multiply parentheses
12x-(6(-4x/2))+2=0
We multiply all the terms by the denominator
12x*2))-(6(-4x+2*2))=0
We add all the numbers together, and all the variables
12x*2))-(6(-4x+4))=0
We add all the numbers together, and all the variables
-4x+12x*2))-(6(=0
Wy multiply elements
24x^2-4x=0
a = 24; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·24·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*24}=\frac{8}{48} =1/6 $
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