6(2x-5)=14+4(x-2)

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Solution for 6(2x-5)=14+4(x-2) equation: 



6(2x-5)=14+4(x-2)

We move all terms to the left:

6(2x-5)-(14+4(x-2))=0

We multiply parentheses

12x-(14+4(x-2))-30=0



We calculate terms in parentheses: -(14+4(x-2)), so:

14+4(x-2)

determiningTheFunctionDomain
4(x-2)+14

We multiply parentheses

4x-8+14

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

12x-4x-6-30=0

We add all the numbers together, and all the variables

8x-36=0

We move all terms containing x to the left, all other terms to the right

8x=36

x=36/8

x=4+1/2

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