6(2x-5)=(4+x)

Solution for 6(2x-5)=(4+x) equation:

6(2x-5)=(4+x)

We move all terms to the left:

6(2x-5)-((4+x))=0

We add all the numbers together, and all the variables

6(2x-5)-((x+4))=0

We multiply parentheses

12x-((x+4))-30=0


We calculate terms in parentheses: -((x+4)), so:

(x+4)

We get rid of parentheses

x+4

Back to the equation:

-(x+4)


We get rid of parentheses

12x-x-4-30=0

We add all the numbers together, and all the variables

11x-34=0

We move all terms containing x to the left, all other terms to the right

11x=34

x=34/11

x=3+1/11