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6(2x-4-x+1)=12
We move all terms to the left:
6(2x-4-x+1)-(12)=0
We add all the numbers together, and all the variables
6(x-3)-12=0
We multiply parentheses
6x-18-12=0
We add all the numbers together, and all the variables
6x-30=0
We move all terms containing x to the left, all other terms to the right
6x=30
x=30/6
x=5
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