6(2x-4)+3=5(3x-1)+5

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Solution for 6(2x-4)+3=5(3x-1)+5 equation: 



6(2x-4)+3=5(3x-1)+5

We move all terms to the left:

6(2x-4)+3-(5(3x-1)+5)=0

We multiply parentheses

12x-(5(3x-1)+5)-24+3=0



We calculate terms in parentheses: -(5(3x-1)+5), so:

5(3x-1)+5

We multiply parentheses

15x-5+5

We add all the numbers together, and all the variables

15x

Back to the equation:

-(15x)



We add all the numbers together, and all the variables

-3x-21=0

We move all terms containing x to the left, all other terms to the right

-3x=21

x=21/-3

x=-7

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