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6(2x-3x)=3(x+4)
We move all terms to the left:
6(2x-3x)-(3(x+4))=0
We add all the numbers together, and all the variables
6(-1x)-(3(x+4))=0
We multiply parentheses
-6x-(3(x+4))=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
-6x-3x-12=0
We add all the numbers together, and all the variables
-9x-12=0
We move all terms containing x to the left, all other terms to the right
-9x=12
x=12/-9
x=-1+1/3
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