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6(2x-3)=8-5(x-5)
We move all terms to the left:
6(2x-3)-(8-5(x-5))=0
We multiply parentheses
12x-(8-5(x-5))-18=0
We calculate terms in parentheses: -(8-5(x-5)), so:We get rid of parentheses
8-5(x-5)
determiningTheFunctionDomain -5(x-5)+8
We multiply parentheses
-5x+25+8
We add all the numbers together, and all the variables
-5x+33
Back to the equation:
-(-5x+33)
12x+5x-33-18=0
We add all the numbers together, and all the variables
17x-51=0
We move all terms containing x to the left, all other terms to the right
17x=51
x=51/17
x=3
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