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6(2x-2)-3(x-8)=4x+8x
We move all terms to the left:
6(2x-2)-3(x-8)-(4x+8x)=0
We add all the numbers together, and all the variables
6(2x-2)-3(x-8)-(+12x)=0
We multiply parentheses
12x-3x-(+12x)-12+24=0
We get rid of parentheses
12x-3x-12x-12+24=0
We add all the numbers together, and all the variables
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4
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