6(2x-10)+3=15

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Solution for 6(2x-10)+3=15 equation: 



6(2x-10)+3=15

We move all terms to the left:

6(2x-10)+3-(15)=0

We add all the numbers together, and all the variables

6(2x-10)-12=0

We multiply parentheses

12x-60-12=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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