6(2x-1)-12=3(7x+4)=

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Solution for 6(2x-1)-12=3(7x+4)= equation: 



6(2x-1)-12=3(7x+4)=

We move all terms to the left:

6(2x-1)-12-(3(7x+4))=0

We multiply parentheses

12x-(3(7x+4))-6-12=0



We calculate terms in parentheses: -(3(7x+4)), so:

3(7x+4)

We multiply parentheses

21x+12

Back to the equation:

-(21x+12)



We add all the numbers together, and all the variables

12x-(21x+12)-18=0

We get rid of parentheses

12x-21x-12-18=0

We add all the numbers together, and all the variables

-9x-30=0

We move all terms containing x to the left, all other terms to the right

-9x=30

x=30/-9

x=-3+1/3

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