6(2x+7)+5x=-4-3(x-2)

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Solution for 6(2x+7)+5x=-4-3(x-2) equation: 



6(2x+7)+5x=-4-3(x-2)

We move all terms to the left:

6(2x+7)+5x-(-4-3(x-2))=0

We add all the numbers together, and all the variables

5x+6(2x+7)-(-4-3(x-2))=0

We multiply parentheses

5x+12x-(-4-3(x-2))+42=0



We calculate terms in parentheses: -(-4-3(x-2)), so:

-4-3(x-2)

determiningTheFunctionDomain
-3(x-2)-4

We multiply parentheses

-3x+6-4

We add all the numbers together, and all the variables

-3x+2

Back to the equation:

-(-3x+2)



We add all the numbers together, and all the variables

17x-(-3x+2)+42=0

We get rid of parentheses

17x+3x-2+42=0

We add all the numbers together, and all the variables

20x+40=0

We move all terms containing x to the left, all other terms to the right

20x=-40

x=-40/20

x=-2

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