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6(2x+3/6)=6(3x+1/6)
We move all terms to the left:
6(2x+3/6)-(6(3x+1/6))=0
We add all the numbers together, and all the variables
6(+2x+3/6)-(6(+3x+1/6))=0
We multiply parentheses
12x-(6(+3x+1/6))+3/6*6=0
We calculate fractions
12x+(-(6(+3x+1*6*6)/()+()/()=0
We calculate terms in parentheses: +(-(6(+3x+1*6*6)/()+()/(), so:
-(6(+3x+1*6*6)/()+()/(
We can not solve this equation
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