6(2x+3)=9(x+3)+6

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Solution for 6(2x+3)=9(x+3)+6 equation: 



6(2x+3)=9(x+3)+6

We move all terms to the left:

6(2x+3)-(9(x+3)+6)=0

We multiply parentheses

12x-(9(x+3)+6)+18=0



We calculate terms in parentheses: -(9(x+3)+6), so:

9(x+3)+6

We multiply parentheses

9x+27+6

We add all the numbers together, and all the variables

9x+33

Back to the equation:

-(9x+33)



We get rid of parentheses

12x-9x-33+18=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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