6(2x+3)=2(3x-2)

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Solution for 6(2x+3)=2(3x-2) equation:



6(2x+3)=2(3x-2)
We move all terms to the left:
6(2x+3)-(2(3x-2))=0
We multiply parentheses
12x-(2(3x-2))+18=0
We calculate terms in parentheses: -(2(3x-2)), so:
2(3x-2)
We multiply parentheses
6x-4
Back to the equation:
-(6x-4)
We get rid of parentheses
12x-6x+4+18=0
We add all the numbers together, and all the variables
6x+22=0
We move all terms containing x to the left, all other terms to the right
6x=-22
x=-22/6
x=-3+2/3

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