6(2x+2)=4(-x-5)

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Solution for 6(2x+2)=4(-x-5) equation: 



6(2x+2)=4(-x-5)

We move all terms to the left:

6(2x+2)-(4(-x-5))=0

We add all the numbers together, and all the variables

6(2x+2)-(4(-1x-5))=0

We multiply parentheses

12x-(4(-1x-5))+12=0



We calculate terms in parentheses: -(4(-1x-5)), so:

4(-1x-5)

We multiply parentheses

-4x-20

Back to the equation:

-(-4x-20)



We get rid of parentheses

12x+4x+20+12=0

We add all the numbers together, and all the variables

16x+32=0

We move all terms containing x to the left, all other terms to the right

16x=-32

x=-32/16

x=-2

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