6(2x+10)=5(3x-4)-2x+10

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Solution for 6(2x+10)=5(3x-4)-2x+10 equation: 



6(2x+10)=5(3x-4)-2x+10

We move all terms to the left:

6(2x+10)-(5(3x-4)-2x+10)=0

We multiply parentheses

12x-(5(3x-4)-2x+10)+60=0



We calculate terms in parentheses: -(5(3x-4)-2x+10), so:

5(3x-4)-2x+10

We add all the numbers together, and all the variables

-2x+5(3x-4)+10

We multiply parentheses

-2x+15x-20+10

We add all the numbers together, and all the variables

13x-10

Back to the equation:

-(13x-10)



We get rid of parentheses

12x-13x+10+60=0

We add all the numbers together, and all the variables

-1x+70=0

We move all terms containing x to the left, all other terms to the right

-x=-70

x=-70/-1

x=+70

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