6(2x+1)=8(x+3)

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Solution for 6(2x+1)=8(x+3) equation: 



6(2x+1)=8(x+3)

We move all terms to the left:

6(2x+1)-(8(x+3))=0

We multiply parentheses

12x-(8(x+3))+6=0



We calculate terms in parentheses: -(8(x+3)), so:

8(x+3)

We multiply parentheses

8x+24

Back to the equation:

-(8x+24)



We get rid of parentheses

12x-8x-24+6=0

We add all the numbers together, and all the variables

4x-18=0

We move all terms containing x to the left, all other terms to the right

4x=18

x=18/4

x=4+1/2

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