6(2x+1)=4x+8(x+3/4)

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Solution for 6(2x+1)=4x+8(x+3/4) equation: 


x in (-oo:+oo)

6*(2*x+1) = 8*(x+3/4)+4*x // - 8*(x+3/4)+4*x

6*(2*x+1)-(8*(x+3/4))-(4*x) = 0

6*(2*x+1)-8*(x+3/4)-4*x = 0

6*(2*x+1)-8*(x+3/4)-4*x = 0

4*x-4*x = 0

0 = 0

0 = 0

x belongs to the empty set

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