6(2x+1)=46-4(3x-2)

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Solution for 6(2x+1)=46-4(3x-2) equation: 



6(2x+1)=46-4(3x-2)

We move all terms to the left:

6(2x+1)-(46-4(3x-2))=0

We multiply parentheses

12x-(46-4(3x-2))+6=0



We calculate terms in parentheses: -(46-4(3x-2)), so:

46-4(3x-2)

determiningTheFunctionDomain
-4(3x-2)+46

We multiply parentheses

-12x+8+46

We add all the numbers together, and all the variables

-12x+54

Back to the equation:

-(-12x+54)



We get rid of parentheses

12x+12x-54+6=0

We add all the numbers together, and all the variables

24x-48=0

We move all terms containing x to the left, all other terms to the right

24x=48

x=48/24

x=2

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