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6(2x+1)=3(4x+1)
We move all terms to the left:
6(2x+1)-(3(4x+1))=0
We multiply parentheses
12x-(3(4x+1))+6=0
We calculate terms in parentheses: -(3(4x+1)), so:We get rid of parentheses
3(4x+1)
We multiply parentheses
12x+3
Back to the equation:
-(12x+3)
12x-12x-3+6=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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