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6(2x+0.5)=4(1+3x)
We move all terms to the left:
6(2x+0.5)-(4(1+3x))=0
We add all the numbers together, and all the variables
6(2x+0.5)-(4(3x+1))=0
We multiply parentheses
12x-(4(3x+1))+3=0
We calculate terms in parentheses: -(4(3x+1)), so:We get rid of parentheses
4(3x+1)
We multiply parentheses
12x+4
Back to the equation:
-(12x+4)
12x-12x-4+3=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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