6(2x+-3)-10=32

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Solution for 6(2x+-3)-10=32 equation: 



6(2x+-3)-10=32

We move all terms to the left:

6(2x+-3)-10-(32)=0

We add all the numbers together, and all the variables

6(2x-3)-10-32=0

We add all the numbers together, and all the variables

6(2x-3)-42=0

We multiply parentheses

12x-18-42=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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